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When 1 mol CrCl(3).6H(2)O is treated wit...

When 1 mol `CrCl_(3).6H_(2)O` is treated with excess of `AgNO_(3)`, 3 mol of `AgCl` are obtained. The formula of the coplex is

A

`[CrCl_(3) (H_(2)O)_(3)] * 3H_(2)O`

B

`[CrCl_(2) (H_(2)O)_(4)]Cl* 2 H_(2)O`

C

`[CrCl(H_(2)O)_(5)]Cl_(2) * H_(2)O`

D

`[Cr(H_(2)O)_(6)Cl_(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
As 3 moles of `AgCl` are obtained when 1 mol of `CrCl_(3) * 6H_(2)O` is treated with excess of `AgNO_(3)` which shows that one molecule of the complex gives three chloride ions in solution . Hence , formula of the complex is `[Cr(H_(2)O)_(6)]Cl_(3)` .
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