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The ionization energies of Li and Na are...

The ionization energies of Li and Na are `520 kJ mol ^-1 and 495 kJ mol ^-1` respectively. The energy required to convert all the atoms present in 7 mg of Li vapours and 23 mg of sodium vapours to their respective gaseous captions respectively are :

A

52 J,49.5 J

B

520 J,495 J

C

49.5 J,52 J

D

495 J,520 J

Text Solution

Verified by Experts

The correct Answer is:
B
No. of moles of Li=`(7)/(1000X7)=10^(-3)`
No. of moles of NA=`(23)/(1000xx23)=10^(-3)`
`therefore` The amount of energies required for `10^(-3)` mole each of Li and Na are 520 `KJX10^(-3) and 495 KJ X10^(-3)` or 520 J and 495 J respectibely.
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