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Arrange the following in decreasing orde...

Arrange the following in decreasing order of dipole moment
(a) Toluene (2) m-Dichlorobenzene
(3) o-Dichlorobenzene (4) p-Dichlorobenzene
(b) BF_(3) (2) `H_(2)S` (3) `H_(2)O`
(c ) cis-1 Chloropropene
(2) Trans -1 -Chloropropene
(3) 1,1-Dichloroethene .

A

`BF_(3) lt H_(2)S lt H_(2)O`

B

`H_(2)S lt BF_(3)ltH_(2)O`

C

`H_(2)O lt H_(2)S lt BF_(3)`

D

`BF_(3) lt H_(2)O lt H_(2)S`

Text Solution

Verified by Experts

The correct Answer is:
A
In `BF_(3)`, dipole moment is zero due to its symmetrical structure. Summations of all dipoles is zero.

In `H_(2)S and H_(2)O` due to unsymmetrical structure net + ve dipole is there `H_(2)O` has higher dipole due to higher electronegativity of oxygen than sulphur.
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