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The bond dissociation energy of gaseous ...

The bond dissociation energy of gaseous `H_(2),Cl_(2)` and `HCl` are `104,58` and `103 kcal mol^(-1)` respecitvely. Calculate the enthalpy of formation for `HCl` gas.

A

`-22` kcal

B

`+22` kcal

C

`+184` kcal

D

`-184` kcal

Text Solution

Verified by Experts

The correct Answer is:
A
`(1)/(2)H_(2)+(1)/(2)Cl_(2) rarr HCl`
`DeltaH=(1)/(2)xx104+(1)/(2)xx58-103=-"22 kcal"`
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