For a reaction, P+Q rarr R+S. The value ...

For a reaction, `P+Q rarr R+S`. The value of `DeltaH^(@)` is `-"30 kJ mol"^(-1) and DeltaS" is "-"100 J K"^(-1)"mol"^(-1)`. At what temperature the reaction will be at equilibrium?

`27^(@)C`

`52^(@)C`

`30^(@)C`

`45^(@)C`

Text Solution

Verified by Experts

The correct Answer is:

`DeltaG=DeltaH-TDeltaS,`
At equilibrium, `DeltaG=0, DeltaH=TDeltaS`
`30000=Txx100`
`T="300 K or "27^(@)C`

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