At what temperature liquid water will be...

At what temperature liquid water will be in equilibrium with water vapour?
`DeltaH_("vap")="40.73 kJ mol"^(-1),DeltaS_("vap")="0.109 kJ K"^(-1)"mol"^(-1)`

A

282.4 K

B

373.6 K

C

100 K

D

400 K

Text Solution

Verified by Experts

The correct Answer is:

B

At equilibrium `DeltaG=0" for "DeltaG=DeltaH-TDeltaS`
`"or T"=(DeltaH)/(DeltaS)=(40.73)/(0.109)="373.6 K"`

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