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PCl(5),PCl(3)andCl(2) are at equilibrium...

`PCl_(5),PCl_(3)andCl_(2)` are at equilibrium at 500 K with concentration 2.1 M `PCl_(3)`, 2.1 M `Cl_(2)and"1.9 "MPCl_(5)`.
The equilibrium constant for the given reaction is
`PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))`

A

2.32

B

1.79

C

4.2

D

3.8

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(c)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=(2.1xx2.1)/(1.9)=2.32`
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