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1 mole of NO 1 mole of O(3) are taken in...

1 mole of NO 1 mole of `O_(3)` are taken in a 10 L vessel and heated. At equilibrium, `50%` of NO (by mass) reacts with `O_(3)` according to the equation :
`NO_((g))+O_(3(g))hArrNO_(2(g))+O_(2(g))`.
What will be the equilibrium constant for this reaction ?

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(,NO_((g)),+,O_(3(g)),hArr,NO_(2(g)),+,O_(2(g))),("Intial conc.",1,,1,,0,,0),("At equilibrium",0.5,,0.5,,0.5,,0.5),("Conc.",(0.5)/(10),,(0.5)/(10),,(0.5)/(10),,(0.5)/(10)):}`
`K_(c)=(0.05xx0.05)/(0.05xx0.05)=1`
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