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18.4 g of N(2)O(4) is taken in a 1 L clo...

18.4 g of `N_(2)O_(4)` is taken in a 1 L closed vessel and heated till the equilibrium is reached.
`N_(2)O_(4(g))rArr2NO_(2(g))`
At equilibrium it is found that 50% of `N_(2)O_(4)` is dissociated . What will be the value of equilibrium constant?

A

0.2

B

2

C

0.4

D

0.8

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(,N_(2)O_(4(g)),hArr,2NO_(2(g))),("Intial conc.",18.4,,0),("No. of moles",(18.4)/(92)=0.2,,),("At equilibrium",0.2-0.1,,2xx0.1),(,=0.1,,=0.2):}`
`K_(c)=(0.2xx0.2)/(0.1)=0.4`
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