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In the system X+2YhArrZ, the equilibrium...

In the system `X+2YhArrZ`, the equilibrium concentration are,
`[X]=0.06" mol L"^(-1),[Y]=0.12" mol L"^(-1)`,
`[Z]=0.216" mol L"^(-1)`. Find the equilibrium constant of the reaction.

A

250

B

500

C

125

D

273

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(0.06)(X)+underset(0.12)(2Y)hArrunderset(0.216)(Z)`
`K_(c)=([Z])/([X][Y]^(2))=(0.216)/(0.06xx0.12xx0.12)=250`
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