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For the reaction a+bhArrc+d, initially c...

For the reaction `a+bhArrc+d`, initially concentrations of a and b are equal and at equilibrium the concentration of will be twice of that of a. What will be equilibrium constant for the reaction ?

A

2

B

9

C

4

D

3

Text Solution

Verified by Experts

The correct Answer is:
C
`underset(x)(a)+underset(x)(b)hArrunderset(2x)(c)+underset(2x)(d)`
`K_(c)=(2x.2x)/(x.x)=(4x^(2))/(x^(2))rArrK_(c)=4`
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