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At 350 K, K(p) for the reaction given be...

At 350 K, `K_(p)` for the reaction given below is `3.0xx10^(10)"bar"^(-1)` at equilibrium. What be the value of `K_(c)` at this temperature ?
`2N_(2(g))+O_(2(g))hArr2N_(2)O_((g))`

A

`7.4xx10^(11)"L mol"^(-1)`

B

`8715xx10^(10)"L mol"^(-1)`

C

`0.08"L mol"^(-1)`

D

`8.715xx10^(11)"L mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(p)=K_(c)(RT)^(Deltan),Deltan=2-3=-1`
`T=350K,R=0.083" bar L K"^(-1)"mol"^(-1)`
`K_(c)=(K_(p))/((RT)^(Deltan))`
`K_(c)=(3xx10^(10)" bar"^(-1))/((0.083" L bar K"^(-1)"mol"^(-1)xx350K)^(-1))`
`=3xx10^(10)"bar"^(-1)xx0.083"L bar K"^(-1)"mol"^(-1)xx350K`
`=8.715xx10^(11)"L mol"^(-1)`
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