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0.6 moles of PCl(5), 0.3 mole of PCl(...

0.6 moles of `PCl_(5)`, 0.3 mole of `PCl_(3)` and 0.5 mole of `Cl_(2)` are taken in a 1 L flask to obtain the following equilibrium ,
`PCl_(5(g))rArrPCl_(3(g))+Cl_(2(g))` If the equilibrium constant `K_(c)` for the reaction is 0.2 Predict the direction of the reaction.

A

Forward direction

B

Backward direction

C

Direction of the reaction cannot be predicted

D

Reaction does not move in any direction.

Text Solution

Verified by Experts

The correct Answer is:
B
`PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))`
`Q_(c)=(0.5xx0.3)/(0.6)=0.25`
`K_(c)=0.2`, Since, `Q_(c)gtK_(c)` reaction will proceed in backward direction.
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