Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

Explanation

Let the base height and area of the first triangle be `b_(1),h_(1)` and `A_(1)` respectively. Let the base, height and area of the second triangle be `b_(2),h_(2)` and `A_(2)` respectively.
`b_(1)=9,h_(1)=5,b_(2)=10` and `h_(2)=6`.
The ratio of areas of two triangles is equal to the ratio of the products of their bases and corresponding heights.
`(A_(1))/(A_(2))=(b_(1)xxh_(1))/(b_(2)xxh_(2))`
`:.(A_(1))/(A_(2))=(9xx5)/(10xx6):.(A_(1))/(A_(2))=3/4`
The ratio of the areas of the triangles is 3:4.