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In DeltaABC and DeltaPQR in a one-to-one...

In `DeltaABC` and `DeltaPQR` in a one-to-one correspndence `(AB)/(QR)=(BC)/(PR)=(CA)/(PQ)` then

A

`DeltaPQR~DeltaABC`

B

`DeltaPQR~DeltaCAB`

C

`DeltaCBA~DeltaPQR`

D

`DeltaBCA~DeltaPQR`

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The correct Answer is:
B
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