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In the figure A-D-C and B-E-C seg DE|| s...

In the figure `A-D-C` and `B-E-C` seg `DE||` side AB. If `AD=5, DC=3, BC=6.4` then find BE.

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In `DeltaABC`,
seg `DE||` side AB …………..(Given)
`:.` by basic proportionality theorem,
`(CD)/(DA)=(CE)/(BE)`
`:.3/6=(6.4-x)/x`
`:.3x=5(6.4-x)`
`:.3x=32-5x`
`:.3x+5x=32`
`:.8x=32`
`:.x=32/8`
`:.x=4`
`BE=x=4`
`BE=4`
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