If `tan theta=3/4` and `theta` is not in first quadrant then `(sin(pi/2+theta)-cot(pi-theta))/(tan((3pi)/2-theta)-cos((3pi)/2+theta))=`

If tan theta = 3/4 and theta is not in the first quadrant then (sin (pi//2 + theta)-cot(pi-theta))/(tan(3 pi//2 - theta)-cos (3pi//2+theta))=

if cos theta=(3)/(5) and theta is not in the first quadrant then (5tan(pi+theta)+4cos(pi+theta))/(5sec(2 pi-theta)-4cot(2 pi+theta))=

If cos theta =(3)/5 and theta is not in the first quadrant , then (5 tan(pi+ theta ) + 4 cos (pi-theta ))/( 5 sec ( 2pi- theta ) - 4 cot (2pi+ theta ))=

Prove that : (cos(pi+theta)cos(-theta))/(sin (pi-theta) cos (pi/2+ theta))= cot^2 theta.

x cot((pi)/(2)+theta)+tan((pi)/(2)+theta)sin theta+csc((pi)/(2)+theta)=0

cos ((3pi)/(2)+theta) cos (2pi+theta) xx [ cot ((3pi)/(2) -theta) + cot (2pi + theta) ] = ?

2cos((pi)/(2)-theta)+3sin((pi)/(2)+theta)-(3sin theta+2cos theta)=

If tan theta=-3/4 and pi/2 < theta < pi, find the values of sin theta,cos theta and cot theta .