A taxi of Bipinbabu travels 14 km Path in 25 minutes . Applying theory of variation find how much path the will go in 5 hours by driving taxi with same speed .

Explanation

Let the distance =s and time =t .
We know that the distance travelled and the time required are always in direct variation .
`therefore s prop t rArr s =kt ……..(1)` (where =`ne` 0= variation constant )
As per question , s =14 km and t =25 minutes .
`therefore` from (1) we get , 14 =k.25 `rArr k =(14)/(25) `
`therefore` from (1) , s=`(14)/(25)`t.........(2)
Now 5 hours =` 5xx60` minutes =300 minutes .
`therefore from (2) we "get" , s=(14)/(25)xx300 ` or s=168 .
`therefore` The required path =168 km.