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Height of a tower is 100sqrt(3) metres. ...

Height of a tower is `100sqrt(3)` metres. The angle to elevation of the top the tower from a point at a distance of 100 metres of foot of the tower is

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

None of these

Text Solution

Verified by Experts

Let the angle of elevation is `theta` and AB is the tower.
As per question, AB `= 100sqrt(3)` metres and BC = 100 metres
`therefore` from the right-angled `deltaABC`, we get,
`tan theta = (AB)/(BC)`
or, `tan theta = (100sqrt(3))/(100) or, tan theta = sqrt(3)`
or, `tan theta = tan60^(@) " " theta = 60^(@)`.
Hence (c) is correct.
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