AC is the hypotenuse with of 100 meters of a right-angled triangle ABC and if AB = `50sqrt(3)` meters, then find the value of `angleC`.

Explanation

Let `angleC = theta`.
As per question, AB `= 50sqrt(3)` m
and AV = 100 m.
Now, from the right-angled triangle ABC, ltbr. `sintheta = (AB)/(AC) ` [ by definition ]
`rArr sin theta = (50sqrt(3))/(100) " " sin theta = (sqrt(3))/(2)`
`rArr sin theta = sin 60^(@) " "rArr theta = 60^(@)`
Hence the value of `angleC = 60^(@)`.