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The components of a vector along the x- ...

The components of a vector along the x- and y- directions are `(n+1)` and 1, respectively. If the coordinate system is rotated by an angle `theta=60^(@)`, then the components change to `n` and 3. The value of `n` is

A

2

B

`cos 60^(@)`

C

`sin 60^(@)`

D

3.5

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The correct Answer is:
To solve the problem step by step, we will follow the information provided in the question and apply the concepts of vector components and rotation. ### Step 1: Identify the initial components of the vector The components of the vector along the x- and y-directions are given as: - \( x_1 = n + 1 \) - \( y_1 = 1 \) Thus, we can represent the vector as: \[ \vec{V} = (n + 1) \hat{i} + 1 \hat{j} \] ### Step 2: Calculate the magnitude of the vector The magnitude of the vector \(\vec{V}\) can be calculated using the formula: \[ |\vec{V}| = \sqrt{(x_1)^2 + (y_1)^2} \] Substituting the values: \[ |\vec{V}| = \sqrt{(n + 1)^2 + 1^2} = \sqrt{(n + 1)^2 + 1} \] ### Step 3: Identify the new components after rotation After rotating the coordinate system by an angle \(\theta = 60^\circ\), the new components of the vector are given as: - \( x_2 = n \) - \( y_2 = 3 \) ### Step 4: Calculate the magnitude of the vector after rotation The magnitude of the vector after rotation can also be calculated as: \[ |\vec{V}| = \sqrt{(x_2)^2 + (y_2)^2} \] Substituting the new values: \[ |\vec{V}| = \sqrt{n^2 + 3^2} = \sqrt{n^2 + 9} \] ### Step 5: Set the magnitudes equal to each other Since the magnitude of the vector remains the same before and after rotation, we can set the two expressions for magnitude equal to each other: \[ \sqrt{(n + 1)^2 + 1} = \sqrt{n^2 + 9} \] ### Step 6: Square both sides to eliminate the square roots Squaring both sides gives: \[ (n + 1)^2 + 1 = n^2 + 9 \] ### Step 7: Expand and simplify the equation Expanding the left side: \[ n^2 + 2n + 1 + 1 = n^2 + 9 \] This simplifies to: \[ n^2 + 2n + 2 = n^2 + 9 \] ### Step 8: Cancel \(n^2\) from both sides Subtract \(n^2\) from both sides: \[ 2n + 2 = 9 \] ### Step 9: Solve for \(n\) Subtract 2 from both sides: \[ 2n = 7 \] Now divide by 2: \[ n = \frac{7}{2} \] ### Final Answer The value of \(n\) is: \[ \boxed{\frac{7}{2}} \]

To solve the problem step by step, we will follow the information provided in the question and apply the concepts of vector components and rotation. ### Step 1: Identify the initial components of the vector The components of the vector along the x- and y-directions are given as: - \( x_1 = n + 1 \) - \( y_1 = 1 \) Thus, we can represent the vector as: ...
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CENGAGE PHYSICS-VECTORS-Exercise Single Correct
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  9. Find the resultant of the three vectors vec(OA), vec(OB) and vec(OC) s...

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  10. Two vectors vec(a) and vec(b) are at an angle of 60^(@) with each othe...

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  11. The resultant of two vectors vec(P) and vec(Q) is vec(R ). If the magn...

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  12. A vector vec(A) When added to the vector vec(B)=3hat(i)+4hat(j) yields...

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  13. ABCDEF is a regular hexagon with point O as centre. The value of vec(A...

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  14. In a two diamensional motion of a particle, the particle moves from po...

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  15. The sum of two forces at a point is 16N. if their resultant is normal...

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  16. The angle between two vector A and B is theta. Vector R is the resulta...

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  17. The resultant of three vectors 1,2, and 3 units whose directions are t...

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  18. A unit vector along the incident ray of light is hat(i). The unit vect...

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  19. The components of a vector along the x- and y- directions are (n+1) an...

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  20. Two point masses 1 and 2 move with uniform velocities vec(v)(1) and ve...

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