Two trains, each of length `100 m` moveing in opposite direction along parallel lines, meet each other with speeds of `50 km h^(-1)` and ` 40 km h^(2)`. If their acceleration are `30 cm s^(-2)` and `20 cm s^(2)` respectively, find the time they will take to pass each other.

Explanation

`V_(rel)=50 +40= 90 km h^(-1) =25 ms^(-1)`
`a_(rel)=30+20=50 cm s^(-1) =0.5 m s^(-2)`
`s_(rel)=u_(rel)t+(1)/(2) a_(rel) t^(2)`
`rArr 100+100=25 t+(1)/(2) 0.5 t^(2)`
Solving, we get `t=10 sqrt(33-50) s`.