A police is chasing a culprit going n a motorbike. The motorbike crosses a turning at a speed of 72 km/h.
The jeep follows it at a speed of 90 km/h, crossing the turning tenseconds later than the bike. Assuming that they travel at constant speeds, how far (in km) from the turning will the jeep catch up with the bike?

Answer

1

Explanation

`V_(p) =90 km h^(-1) =25 m s^(-1)`
`V_(c) =72 k m h^(-1) =20 m s^(-1)`
In `10 s` culprit reaches point `B` and `A`. Distance covered by culprit, `S=vt =20 xx 10 =200 m`.
At time `t=10 s`, the police jeep is `200 m` behind the culparit. Relative velocity between jeep and culprit is s`25 -20 =5 m s^(-1)`.
Time `=(S)/(V) =(200)/(5) =40 s` (Relative velcity is considered) In `40 s` the police jeep will move from a to a distance `S`. Where `S=vt =25 xx 40 =100 m =1.0 km` away. The jeep will catch up with the bike `1 km` far from the turing.