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A body of mass 2 kg has an initial veloc...

A body of mass `2 kg` has an initial velocity of `3 m s^-1` along `OE` and it is subjected to a force of `4 N` in `O F` direction perpendicular to `O E`. Find the distance of the body from `O` after `4 s`.
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Text Solution

Verified by Experts

Body moves horizontally with constant initial velocity `3 ms^-1` upto `4 s`.
`:. x = ut = 3 xx 4 = 12 m`
And in perpendicular direction it moves under the effect of constant force with zero initial velocity upto `4 s`.
`:. y = u t + (1)/(2) (a) t^2 = 0 + (1)/(2)((F)/(m)) t^2 = (1)/(2)((4)/(2)) 4^2 = 16 m`
So its distance from `O` is given by
`d = sqrt(x^2 + y^2) = sqrt((12)^2 + (16)^2) = 20 m`.
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Knowledge Check

  • A body mass 2kg has an initial velocity of 3 metre//sec along OE and it is subject to a force of 4N in a direction perpendicular to OE. The distance of body from O after 4 sec will be:

    A
    12 metres
    B
    20 metres
    C
    8 metres
    D
    48 metres
  • A body of mass 8 kg is moving with a velocity of 4 m/s, find its momentum.

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    2
    B
    64
    C
    32
    D
    4
  • Assertion : A body of mass 4 kg has an initial velocity 5hat(i)ms^(-1) . It is subjected to a force of 4hat(j)N . The displacement of body from origin after 4 s will be 21.5 m . Reason : The equation v=u+a t can be applied to obtain v if a is constant.

    A
    If both Assertion and Reason are correct and Reason is the correct explanation of assertion.
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    If both Assertion and Reason are correct but Reason in not the correct explanation of Assertion.
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