Home
Class 11
PHYSICS
A 400 - m wide river is flowing at a rat...

A `400 - m` wide river is flowing at a rate of `2.0 m s^-1`. A boat is sailing with a velocity of `10 m s^-1` with respect to the water, in a direction perpendicular to the river.
(a) Find the time taken by the boat to reach the opposite bank.
(b) How far from the point directly opposite to the starting point does the boat reach the opposite bank ?
( c) In what direction does the boat actually move ?

Text Solution

Verified by Experts

(a) Time taken to cross the river
`t = (d)/(v_y) = (400 m)/(10 ms^-1) = 40 s`
(b) Drift `(x) = (v x) (t)`
=`(2 ms^-1)(40 s) = 80 m`
( c) Actual direction of boat,
`theta = tan^-1((10)/(2)) = tan^-1 s`,
(downstream) with the river flow.
.
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS-2

    CENGAGE PHYSICS|Exercise Exercise 5.4|11 Videos

  • KINEMATICS-2

    CENGAGE PHYSICS|Exercise Exercise Subjective|40 Videos

  • KINEMATICS-2

    CENGAGE PHYSICS|Exercise Exercise 5.2|25 Videos

  • KINEMATICS-1

    CENGAGE PHYSICS|Exercise Integer|9 Videos

  • KINETIC THEORY OF GASES

    CENGAGE PHYSICS|Exercise Compression|2 Videos

Similar Questions

Explore conceptually related problems

A river 400 m wide is flowing at a rate of 2.0 m//s. A boat is sailing at a velocity of 10.0 m//s with respect to the water In a direction perpendicular to the river. (a) Find the time taken by the boat to reach the opposite bank. (b) How far from the point directly opposite to the starting point does the boat reach the opposite bank?

A river 500m wide is flowing at a rate of 4 m//s. A boat is sailing at a velocity of 10 m//s with respect to the water, in a direction perpendicular to the river. The time taken by the boat to reach the opposite bank

In the previous problem, How far from the point directly opposite to the starting point does the man reach the opposite bank

A river is 20 m wide. River speed is 3 m//s. A boat starts with velocity 2sqrt2 m//s at angle 45^@ from the river current (relative to river) (a) Find the time taken by the boat to reach the opposite bank. (b) How far from the point directly opposite to the starting point does the boat reach the opposite bank?

A river 60m wide is flowing at a rate of 4m/s .A boat is sailing at a velocity of 20 m/s with respect to the river in a direction making an angle 37^(@) with the direction of river flow.Find time taken by the boat in seconds to reach the opposite bank. (A) 2 (B) 3 (C) sqrt(6) (D) 5

A ,man wishing to cross a river flowing with velocity u jumps at an angle theta with the river flow. (a) Find the net velocity of the man with respect to ground if he can swim with speed v in still water. (b) In what direction does the boat actually move ? ( c) Find how far from the point directly opposite to the starting point does the boat reach the opposite bank, if the width of the river is d .

A river is flowing towards with a velocity of 5 m s^-1 . The boat velocity is 10 ms^-1 . The boat crosses the river by shortest path. Hence,

Velocity of the boat with respect to river is 10m/s. From point A it is steered in the direction shown. Where will it reach on the opposite bank ?

Knowledge Check

  • A river 500m wide is flowing at a rate of 4 m//s. A boat is sailing at a velocity of 10 m//s with respect to the water, in a direction perpendicular to the river. The time taken by the boat to reach the opposite bank

    A
    `30s`
    B
    `40s`
    C
    `50s`
    D
    `60s`

  • In the previous problem, How far from the point directly opposite to the starting point does the man reach the opposite bank

    A
    `1//6sqrt(3)km`
    B
    `2//3sqrt(3)km`
    C
    `4//3sqrt(3) km`
    D
    `5//sqrt(3) km`

  • A river is flowing towards with a velocity of 5 m s^-1 . The boat velocity is 10 ms^-1 . The boat crosses the river by shortest path. Hence,

    A
    The direction of boat's velocity is `30^@` west of north.
    B
    The direction of boat's velocity is north - west.
    C
    Resultant velocity is `5 ms^-1`.
    D
    Resultant velocity of boat is `5 sqrt(2) m s^-1`.