A man standing on the roof a house of height `h` throws one particle vertically downwards and another particle horizontally with same velocity `u`. Find the ratio of their velocities when they reach the earth's surface.

Options

A. `4 : 1`
B. `3 : 1`
C. `1 : 2`
D. `1 : 1`

Answer

D

Explanation

For first particle : `v^2 = u^2 + 2 g h`
`rArr v = sqrt(u^2 + 2 gh))`
For second particle :
`v = sqrt(v_x^2 + v_y^2) = sqrt(u^2 + (sqrt(2 g h))^2)`
=`sqrt(u^2 + 2 gh)`
So the ratio of velocities will be `1 : 1`.
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