Two guns are situated at the top of a hill firing the shots at the same speed. One gun fires the shot horizontally and other gun fires the shot at an angle of `60^@` with horizontal. Two two shots collide in air. If the time taken by horizontal shot to reach the point of collision in `3 seconds`, find the time interval between two shots.

Explanation

Let stones meet at `P`.
`rArr (ut^2)/(2) = ut_1 rArr t_2 = 2 t_1` …(i)
Given `t_1 = 3 sec`
Hence `t_2 = 6 sec`
It means `(t_2 - t_1) = 3 sec`
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