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A particle is moving in a circle of radi...

A particle is moving in a circle of radius `r` centred at `O` with constant speed `v`. What is the change in velocity in moving from `A` to `B` `(/_ AOB = 40^@)` ?

A

`2 v sin 20^@`

B

`4 v sin 40^@`

C

`2 v sin 40^@`

D

`v sin 20^@`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Change in velocity `= vec v_f - vec v_i`
Its magnitude is `(sqrt(v^2 + c^2 - 2v v cos 40^@))`
=`2 v sin 20^@`
.
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