A particle is projected from ground at some angle with the horizontal. Let `P` be the point at maximum height `H`. At what height above the point `P` should the particle be aimed to have equal to maximum height ?

Options

A. H
B. 2 H
C. H//2
D. 3 H

Answer

A

Explanation

(a) `AC = R//2, PC = H`
We have to find `h = MP`.
From the figure in previous question, we know that if `H = R`, then
`tan theta = 4`
Now `tan theta = (MC)/(AC) = (MP + PC)/(AC)`
`4 = (h + H)/(R //2) rArr 4 = ((h + H)2)/(H) rArr h = H`.
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