In the above problem, what is the angle of projection with horizontal ?

Options

A. `tan^-1 (1//4)`
B. `tan^-1 (4//3)`
C. `tan^-1 (3//4)`
D. `tan^-1 (1//2)`

Answer

B

Explanation

(b) `tan theta = (v_y)/(v_x) = (8)/(6) = (4)/(3) or theta = tan^-1 (4)/(3)`.