A ball thrown by one player reaches the other in `2 s`. The maximum height attained by the ball above the point of projection will be about.

Options

A. 2.5 m
B. 5 m
C. 7.5 m
D. 10 m

Answer

B

Explanation

(b) `t = (2 u sin theta)/(g) or 2 =(2 u sin theta)/(g) rArr u sin theta = g`
`h_m = (u^2 sin^2 theta)/(2 g) = (g^2)/(2 g) = (g)/(2) = 5m`.