A body of mass m is projected horizontally with a velocity v from the top of a tower of height h and it reaches the ground at a distance x from the foot of the tower. If a second body of mass 2m is projected horizontally from the top of a tower of height 2h, it reaches the ground at a distance 2x from the foot of the tower. The horizontal velocity of the second body is :

Options

A. v
B. 2 v
C. `sqrt(2) v`
D. v//2

Answer

C

Explanation

( c) `x = v sqrt((2 h)/(g)), 2x = v' sqrt((2(2 h))/(g))` Solve to get `v' = (sqrt(2)) v`.