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In the time taken by the projectile to r...

In the time taken by the projectile to reach from `A` to `B` is `t`. Then the distance `AB` is equal to.
.

A

`(ut)/(sqrt(3))`

B

`(sqrt(3) ut)/(2)`

C

`sqrt(3) ut`

D

`2 ut`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Horizontal component of velocity, `u_H = u cos 60^@ = (u)/(2)`
`AC = u_H xx t = (ut)/(2)`
and `AB = AC sec 30^@ = ((ut)/(2)) ((2)/(sqrt(3))) = (ut)/(sqrt(3))`.
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