The angular velocity of a particle moving in a circle of radius `50 cm` is increased in 5 min from `100` revolutions per minute to `400` revolutions per minute. Find the tangential acceleration of the particle.

Options

A. `60 m s^-2`
B. `pi//30 m s^-2`
C. `pi//15 m s^-2`
D. `pi//60 m s^-2`

Answer

D

Explanation

(d) `prop = (omega_2 - omega_1)//t = (400 - 100)//5 = 60 rev min^-2`
=`(60 xx 2 pi)/((60))^2 = (2 pi)/(60) rad s^-2`
`a_t = prop r = (2 pi)/(60) xx (50)/(100) = (pi)/(60) ms^-2`.