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The ring M(1) and block M(2) are held in...

The ring `M_(1)` and block `M_(2)` are held in the position shown in fig. Now the system is released. If `M_(1) gt M_(2)`, find `V_(1)//V_(2)` wheb the ring `m_(1)` slides down along the smooth fixed vertical rod by the distance h.

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To solve the problem, we need to analyze the motion of the ring \( M_1 \) and the block \( M_2 \) when the system is released. Here’s a step-by-step solution: ### Step 1: Understand the System The system consists of a ring \( M_1 \) sliding down a smooth vertical rod and a block \( M_2 \) hanging from a pulley. When \( M_1 \) slides down by a distance \( h \), \( M_2 \) will move upward. ### Step 2: Establish the Relationship Between Distances When the ring \( M_1 \) moves down by a distance \( h \), the block \( M_2 \) will move up by a distance \( h \) as well. However, due to the pulley system, the relationship between the distances moved by \( M_1 \) and \( M_2 \) is not direct. ...
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