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During a heavy rain hailstones of averag...

During a heavy rain hailstones of average size 1.0 cm in diameter fall with an average speed of 20 m/s. Suppose 2000 hailstones strike every square meter of a `10mxx10m` roof perpendicularly in one second and assume that the hailstones do not rebound. Calculate the average force exerted by the falling hailstones on the roof. Density of a hailstone is `900 (kg)/m^3`

Text Solution

Verified by Experts

Force applied by hail stone.
`|F|=(Delta p)/(Delta t)=|(mvec(v)_(f)-mvec(v)_(i))/(Delta t)|=|(0-mvec(v)_(i))/(Delta t)|=(mvec(v)_(i))/(Delta t)`
`|F|=(2000 xx 10 xx 10 xx 4/3 pi((1)/(2 xx 100))^(3) xx 900 xx 20)/(1)`
`= 1900 N`.
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