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A smooth block of mass m is connected wi...

A smooth block of mass m is connected with a spring of stiffness `k(=20Nm^(-1)` )and natural length `l_(0)=0.25 m`. If the block is pulled such that the new length of the spring becomes `l=0.3m`, find the acceleration of the block at the moment when it is released from given positon.

A

`-1/m` `m//s^2`

B

`1/m^2` `m//s^2`

C

`3/(2m)` `m//s^2`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
A
Given spring constant `k=20Nm^(-1)`
Initial length =`0.25 m`
Final length =`0.30 m`
`Delta x =0.30 -0.25 = 0.05 m (rarr)`
Mass of the block = m
`vec(F)=-kvec(x)impliesma=-kDeltax`
`a=-(k Delta x)/(m)=(-20 xx0.05)/(m)=-(1)/(m)`
Acceleration = `1//m (larr)`.
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