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A particle of mass m moving with velocity u makes an elastic one-dimentional collision with a stationary particle of mass `m`. They come in contact for a very small time `t_0`. Their force of interaction increases from zero to `F_0` linearly in time `0.5t_0`, and decreases linearly to zero in further time `0.5t_0` as shown in figure. The magnitude of `F_0` is

A

`m u//T`

B

`2 m u//T`

C

`4 m u//T`

D

`m u//2T`

Text Solution

Verified by Experts

The correct Answer is:
C

Area under the force-time graph is impules, and impulse is change in momentum.
Area of graph=change in momentum
`implies 1/2 TF_(0)=2 m u implies F_(0)=(4m u)/(T)`.
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