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Two beads of equal masses m are attached...

Two beads of equal masses `m` are attached by a string of length `sqrt2a` and are free to move in a smooth circular ring lying in a vertical plane as shown in figure. Here a is the radius of the ring. Find the tension and acceleration of `B` just after the beads are released to move.

A

Zero

B

mg

C

`sqrt(2)mg`

D

`mg//sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
As shown in fig. from FBD of A,
`T cos 45^(@)=ma` …(i)
From FBD of B:
`Mg-T cos 45^(@)=ma`..(ii)

From (i) and (ii) we get `T=mg//sqrt(2)`.
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