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A particle of small m is joined to a ver...

A particle of small m is joined to a very heavy body by a light string passing over a light pulley. Both bodies are free to move. The total downward force on the pulley is

A

`gt gtmg`

B

`4mg`

C

`2mg`

D

`mg`

Text Solution

Verified by Experts

The correct Answer is:
B
`T=(2m Mg)/(m+M) =(2mg)/(1+(m)/(M)) ~= 2mg`
Hence total downward force is `2T=4mg`.
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Knowledge Check

  • In the figure shown, a particle of small mass m is joined to a very heavy mass M (M >> m) by a light string passing over a light pulley. The total downward force on the pulley by the string is :

    A
    mg
    B
    2 mg
    C
    4 mg
    D
    (M + m) g

  • Two masses M and m(M gt m) are joined by a light string passing over a smooth light pulley.

    A
    The acceleration of each block is `((M-m)/(M+m))g`
    B
    The tension in the string is `(2Mmg)/(M+m)`
    C
    The centre of mass of the 'M plus m' system moves down with an acceleration of `g((M-m)/(M+m))^(2)`
    D
    The tension in the string by which the pulley is attached to the rodd is `(M +m)g`

  • Two masses m and M(m lt M) are joined by a light string passing over a smooth and light pulley (as shown)

    A
    the acceleration of each mass is `((M-m)/(M+m))g`
    B
    the tension in the string connecting masses is `((2Mm)/(M+m))g`
    C
    the thrust acting on the pulley is `((4Mm)/(M+m))g`
    D
    None of the above

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