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A particle of small m is joined to a very heavy body by a light string passing over a light pulley. Both bodies are free to move. The total downward force on the pulley is

A

`gt gtmg`

B

`4mg`

C

`2mg`

D

`mg`

Text Solution

Verified by Experts

The correct Answer is:
B
`T=(2m Mg)/(m+M) =(2mg)/(1+(m)/(M)) ~= 2mg`
Hence total downward force is `2T=4mg`.
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