Two uniform solid cylinders A and B each of mass 1 kg are connected by a spring of constant `200Nm^(-1)` at their axles and are placed on a fixed wedge as shown in fig.There is no friction between cylinders and wedge. The angle made by the line AB with the horizontal, in equilibirum is

Options

A. `0^(@)`
B. `15^(@)`
C. `30^(@)`
D. None of these

Answer

C

Explanation

In equlibrium, if `theta` is the required angle
Cylinder A:
`mg sin 60^(@)=kx cos (60^(@)-theta)`
Cylinder B:
`mg sin 30^(@) = kx cos (30^(@)+theta)`
`=kx sin (60^(@)-theta)` on solving `theta=30^(@)`.