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Two blocks A and B each of mass m are pl...

Two blocks A and B each of mass m are placed on a smooth horizontal surface. Two horizontal force F and 2F are applied on blocks A and B, respectively, as shown in fig. Block A does not slide on block B. Then then the normal reaction acting between the two blocks is (assume no friction between the blocks)

A

F

B

`F//2`

C

`(F)/(sqrt(3))`

D

`3F`

Text Solution

Verified by Experts

The correct Answer is:
D
Acceleration of two mass system is
`a=(F)/(2m)` leftwards. FBD of block A is shown in below.
`N cos 60^(@)-F=ma=(mF)/(2m)`
Solving, we get `N=3F`.
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