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In fig., a man true mass M is standing o...

In fig., a man true mass M is standing on a weighing machine placed in a cabin. The cabin is joined by a string a body of mass m. Assuming no friction, and negligible mass of cabin and weighing machine, the measured mass of man is (normal force between the man and the machine is proportional to the mass)

A

The measured mass of man is `(Mm)/((M+m))`

B

The acceleration of man is `(mg)/((M+m))`.

C

The acceleration of man is `(Mg)/((M+m))`.

D

The measured mass of man is `M`

Text Solution

Verified by Experts

The correct Answer is:
A, C
`Mg-T=Ma` ..(i)
`T=ma` ..(ii)
Solving Eqs. (i) and (ii) , `a=(Mg)/(M+m)`
FBD of man,
`Mg-N = Ma implies N=(Mmg)/((M+m))`.
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