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Seven pulleys are connected with the hel...

Seven pulleys are connected with the help of three light string as shown in fig.Consider `P_(3),P_(4),P_(5)` as light pulleys and pulleys `P_(6)` and `P_(7)` have masses m each. For this arrangement, mark the correct statement(s)

A

Tension in the string connecting `P_(1),P_(3) and P_(4)` is zero.

B

Tension in the string connecting `P_(1), P_(3) and P_(4)` is `mg//3`

C

Tension in all the three strings are same and equal to zero.

D

Acceleration of `P_(6)` is g downwards and that of `P_(7)` is g upwards.

Text Solution

Verified by Experts

The correct Answer is:
A, C
First of all, draw FBD of `P_(3)`. Let tensions, in three strings be `T_(1),T_(2)` and `T_(3)`, respectively.
`2T_(1)-T_(1)=0xxa implies T_(1)=0`

Now draw FBD of `P_(4) and P_(5)` .
`2T_(1)-T_(2)=0 implies T_(2)=0`
`2T_(2)-T_(3)=0 implies T_(2)=T_(3)=0`
So forces acting of `P_(6) and P_(7)` will be that of gravity and they will be in free fall.Hence acceleration of each of them will be g down wards.
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