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A block of mass m is placed on a wedge T...

A block of mass m is placed on a wedge The wedge can be accelerated in four manners marked as `(1),(2),(3)` and (4) as shown. If the normal reactions in situation `(1),(2),(3)` and (4) are `N_(1),N_(2),N_(3)` and `N_(4)` respectively and acceleration with which the block slides on the wedge in situation are `b_(1),b_(2),b_(3)` and `b_(4)` respectively then

A

`N_(3) gt N_(1) gt N_(2) gtN_(4)`

B

`N_(4) gt N_(3) gt N_(1) gtN_(2)`

C

`b_(2) gt b_(3) gt b_(4) gtb_(1)`

D

`b_(2) gt b_(3) gt b_(1) gtb_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A, C

Balancing force perpendicular to incline
`N_(1) = mg cos 37^(@)+ma sin 37^(@)`
`N_(1)=4/5 mg +3/5ma`
And along incline

`mg sin 37^(@)-ma cos 37^(@) =mb_(1)`
`b_(1)=3/5g-4/5 a`
Similarly, for this case, we get

`N_(2)=4/5 mg-3/5 ma`
and `b_(2)=3/5 g +4/5 a`
similary for this case we get

`N_(3)=4/5 mg +4/5 ma`
`b_(3)=3/5 g+ 3/5 a`
Similarly for this case, we get
`N_(4)=4/5 mg -4/5 ma`
and `b_(4)=3/5 g-3/5 a`.
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