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You are designing an elevator for a hosp...

You are designing an elevator for a hospital. The force exerted on a passenger by the floor of the elevator is not to exceed 1.60 times the passenger's weight. The elevator accelerates upwards with constant acceleration for a distance of 3.0 m and then starts to slow down. What is the maximum speed (in `ms^(-1)`) of the elevator?

Text Solution

Verified by Experts

The correct Answer is:
6
Consinder the force on the person:

`Sigma F_(y)=ma_(y)`
`n-mg=ma`
`n=1.6 mg`
So, `a=0.60 g = 6 ms^(-2)`
`v^(2)=u^(2)+2as = 0^(2)+2 xx 6 xx 3`
`implies v=6ms^(-1)`
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