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Calculate percentage error in determinat...

Calculate percentage error in determination of time period of a pendulum.
`T = 2pi sqrt(l/g)`
where, l and g are measured with `+-1%` and `+-2%`.

A

`pm1.05%`

B

`pm1.15%`

C

`pm1.5%`

D

`pm0.05%`

Text Solution

Verified by Experts

The correct Answer is:
C
`(DeltaT)/Txx100=pm((1)/(2)xx(Deltal)/(l)xx100+(1)/(2)xx(Deltag)/(g)xx100)`
`=pm((1)/(2)xx1+(1)/(2)xx2)=pm1.5%`
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