The dimensions of `a/b` in the equation `P=(a-t^(2))/(bx)` where `P` is pressure, `x` is distance and `t` is time are

Options

A. `[M^(2)LT^(-3)]`
B. `[MT^(-2)]`
C. `[LT^(-3)]`
D. `[ML^(3)T^(-1)]`

Answer

B

Explanation

Where p=pressure, t=time
`[pbx]=[a]=[t^(2)]`
Hence, `[b]=([t^(2)])/([px])`
Dimensions of `(a)/(b)=[px]=[MT^(-2)]`