The effect of rotation of the eath on the value of acceleration deu to gravity g is

Options

A. maximum at the equator and minimum at the poles
B. minimum at the equator and maximum at the poles
C. maximum at both poles
D. minimum at both poles

Answer

A

Explanation

As `g=g-omega^(2)R cos^(2) lambda`
The latitude is denoted by `lambda` for poles `lambda=90^(@)` and for equator `lambda=0^(@)`
(i) substituting `lambda=90^(@)` in the above expression we get
`g_("poles")=g-omega^(2)R cos^(2) 90^(@) rarr g_("pole")=g`
i.e there is no effect of rotational motion of the earth on the value of g at the poles
(ii) substituting `lambda=0^(@)` in the above expression we get
`g_("equator") =g-omega^(2) cos^(2) 0^(@)=g-omega^(2)R`
i.e the effect of rotation of earth on the value of g at the equator is maximum