A particle is in linear SHM of amplitude A and time period T. If v refers to its average speed during any interval of T/3 , then the maximum possible value of v is

Options

A. `(3 sqrt(3))/(T)A`
B. `(sqrt(3)A)/(T)`
C. `(2 sqrt(3))/(T)A`
D. `(3A)/(T)`

Answer

A

Explanation

`(T)/(3)` means `120^(@)` in reference circle. Maximum possible value of v is near mean position between P and Q

`therefore" "v = ("Distance")/("Time")=(sqrt(3)A)/((T//3))=(3 sqrt(3)A)/(T)`